1.

x g of H_2O_2 require 100 mL of M/5 KMnO_4 in a titration in a solution having pOH=1.0 which of following is/are correct ?

Answer»

The value of x is 1.7 g
The value of x is 0.34 g
`MnO_4^-` CHANGES to `MnO_4^(-2)`
`H_2O_2` CHANGE to `O_2`

SOLUTION :pOH=1 strong basic MEDIUM
`implies MnO_4^(-)toMnO_4^(-2) (n=1)`
`2OH^(-)+H_2O_2 to O_2+2H_2O+2e^(-)`
meq. of `H_2O_2` = meq of `MnO_4^(-)`
`(x/34)/2xx1000=100xx1/5xx1 implies x=0.34 g`


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