X gm of KHC_(2)O_(4) requires 100 ml of 0.02 M KMnO_(4) in acidic medium. In another experiment, y gm of KHC_(2)O_(4) requires 100 mkl of 0.05 M Ca(OH)_(2). The ratio of x and y is

X gm of KHC_(2)O_(4) requires 100 ml of 0.02 M KMnO_(4) in acidic medi

1.	X gm of KHC_(2)O_(4) requires 100 ml of 0.02 M KMnO_(4) in acidic medium. In another experiment, y gm of KHC_(2)O_(4) requires 100 mkl of 0.05 M Ca(OH)_(2). The ratio of x and y is
Answer» `1:1` `1:2` `2:1` `5:4` Solution :Eqts of `KHC_(2)O_(4)` = Eq of `KMnO_(4)` `(x)/((MW)/(2))=(100xx0.02xx5)/(1000)"......."(1)` Eqts of `KHC_(2)O_(4)` = Eq of `Ca(OH)_(2)` `(y)/(MW)=(100xx0.05xx2)/(1000)""......(2)` from `(1), (2)(2x)/(y)=1""x:y=1:2`