X has pens and pencils which together are 40 in number. If he had 5 mo

1.	X has pens and pencils which together are 40 in number. If he had 5 more pencils and 5 less pens, the number of pencils would have become 4 times the number of pens. Find the original number of pens. (a) 10 (b) 11 (c) 12 (d) 13
Answer» (d) 13 Let the number of pencils and pen with X be x and y respectively, Given, x + y = 40 ........(i) Also (x + 5) = 4(y – 5) \(\Rightarrow\)x + 5 = 4y – 20 \(\Rightarrow\) x – 4y = –25 ......(ii) Subtracting eqn (ii) from eqn (i), we get 5y = 65 \(\Rightarrow\) y = 13.

X has pens and pencils which together are 40 in number. If he had 5 more pencils and 5 less pens, the number of pencils would have become 4 times the number of pens. Find the original number of pens. (a) 10 (b) 11 (c) 12 (d) 13

Answer»

(d) 13

Let the number of pencils and pen with X be x and y respectively,

Given, x + y = 40 ........(i)

Also (x + 5) = 4(y – 5)

\(\Rightarrow\)x + 5 = 4y – 20

\(\Rightarrow\) x – 4y = –25 ......(ii)

Subtracting eqn (ii) from eqn (i), we get

5y = 65

\(\Rightarrow\) y = 13.