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x के लिए हल कजिए - `cos(tan^(-1)x)=sin(cot^(-1)""(3)/(4))` |
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Answer» माना ` cot^(-1)""(3)/(4)=theta implies cot theta=(3)/(4)` इसलिए `sin theta=(4)/(5)implies theta=sin^(-1)""(4)/(5)` माना `tan^(-1)x=phiimplies tan phi=x ` इसलिए ` cos phi=(1)/(sqrt(1+x^(2)))` अतः `sin(cot^(-1)""(3)/(4))=sin theta= sin(sin^(-1)""(4)/(5))=(4)/(5)` तथा `cos(tan^(-1)x)=cos phi=(1)/(sqrt(1+x^(2)))` इसलिए `(1)/(sqrt(1+x^(2)))=(4)/(5)` `implies (1)/(1+x^(2))=(16)/(25)implies x=pm""(3)/(4)` अतः `x=pm(3)/(4)` |
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