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` (x log x ) (dy)/(dx) + y = 2 log x ` |
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Answer» Correct Answer - `y(logx) = (log x ) ^(2) +C ` ` (dy)/(dx) + (1)/(x log x ) * y = (2)/(x)` ` IF = e ^(int (1)/(x log x )) dx = e ^(int (1)/(t) dt) = e ^( log t ) = t = log x ` |
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