x millimole of KlO_(3) react completely with y millimole of KI to give I_(2) quantitatively. It z millimole of hypo are required for complete titration against the I_(2) product, then

x millimole of KlO_(3) react completely with y millimole of KI to give

1.	x millimole of KlO_(3) react completely with y millimole of KI to give I_(2) quantitatively. It z millimole of hypo are required for complete titration against the I_(2) product, then
Answer» `Z=6x` `6y=5z` `5x=y` `x+y=2x` Solution :`KIO_(3)+KIrarrI_(2)` m eq `KIO_(3)` = m eq KI = m eq `I_(2)` `x xx5=yxx1=nxx(5)/(3)` `I_(2)+Na_(2)S_(2)O_(3)rarrNa_(2)S_(4)O_(6)+NaI` m eq `I_(2)` = m eq `Na_(2)S_(2)O_(3)` `x xx2=zxx1` `implies x=(z)/(2)implies5x=y=(5z)/(6)`.