X ml of H_(2) gas effuses through a hole in a container in 5 seconds. The time taken for the effusion of the same volume of the gas specified below under identical conditions is

X ml of H_(2) gas effuses through a hole in a container in 5 seconds.

1.	X ml of H_(2) gas effuses through a hole in a container in 5 seconds. The time taken for the effusion of the same volume of the gas specified below under identical conditions is
Answer» 10 seconds : He 20 seconds : `O_(2)` 25 seconds : CO 55 seconds : `CO_(2)` Solution :`(r_(H_(2)))/(r_(X))=sqrt((M_(X))/(M_(H_(2))))" or " (X//5)/(X//t)=sqrt((M_(X))/(2))` or `(t)/(5)=sqrt((M_(X))/(2))` The equaloty HOLDS GOOD only for (b).