X(s)hArrY(g)+2Z(g) A(s)hArrY(g)+B(g) Consider both these equilibrium to be established simultaneously in a closed container. At equilibrium, pressure of Z "and" B were found to be same and sum of pressure of Z & B is 10 atm more than that of species Y. Find ratio of standard gibb's energy of two reactions.

X(s)hArrY(g)+2Z(g) A(s)hArrY(g)+B(g) Consider both these equilibrium

1.	X(s)hArrY(g)+2Z(g) A(s)hArrY(g)+B(g) Consider both these equilibrium to be established simultaneously in a closed container. At equilibrium, pressure of Z "and" B were found to be same and sum of pressure of Z & B is 10 atm more than that of species Y. Find ratio of standard gibb's energy of two reactions.
Answer» `20` `2.303log_(10)20` `log_(10)3sqrt144` `(3+log12)/(2+log6)` Solution :`X(s)hArrY(g)+2Z(g) A(s)hArrY(g)+B(g)` `t=eq. (a+b)2a t=eq. (a+b) b` given `P_(z)=P_(B)` `2a=b` and `P_(z)+P_(B)=P_(Y)+10` `(2a+b)=(a+b)+10` `a=10atm` `THEREFORE b=20atm` `K_(P_(1))=(a+b)(2a)^(2)=(30)(400)=12000` `k_(P_(2))=(a+b)(b)=(30)(20)=600` `DeltaG=-RTInK` `(DeltaG_(1))/(DeltaG_(2))=(lnK_(1))/(lnK_(2))=(log12000)/(log600)=(3+log12)/(2+log6)`