InterviewSolution
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`(x)/((x+1)(x+2))` |
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Answer» `int(x)/((x+1)(x+2))dx=I" "` (माना ) माना `(x)/((x+1)(x+2))=(A)/((x+1))+(B)/((x+2))` `rArr" "(x)/((x+1)(x+2))=(A(x+2)+B(x+1))/((x+1)(x+2))` `rArr" "x=A(x+2)+B(x+1)` `{:(x=-1,"तो ",-1=A(-1+2)+0,rArr.,A=-1),(x=-2,"तो ",-2=0+B(-1),rArr.,B=2):}` `therefore" "I=int(x)/((x+1)(x+2))dx` `=int((-1))/(x+1)dx+int(2)/(x+2)dx` `" "=-log(x+1)+2log(x+2)+C` `" "=-log(x+1)+log(x+2)^(2)+C` `" "=log|((x+2)^(2))/(x+1)|+C` |
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