1.

`x(x+1)(x+2)(x+3)-8`

Answer» `x(x+1)(x+2)(x+3)-8=x(x+1)(x+2)(x+3)-8`
`x(x+3)(x+1)(x+2)-8`
`(x^(2)+3x)(x^(2)+3x+2)-8`
`=(x^(2)+3x)^(2)+2(x^(2)+3x)-8`
`(x^(2)+3x)^(2)+4(x^(2)+3x)-2(x^(2)+3x)-8`
`=(x^(2)+3x)(x^(2)+3x+4)-2(x^(2)+3x+4)`
`=(x^(2)+3x-2)(x^(2)+3x+4)`


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