1.

{{:((|x|)/(x)","if x ne 0 ),(0"," if x = 0 ):}

Answer»

Solution :`{{:((|x|)/(x)","if x NE 0 ),(0"," if x = 0 ):}`
at x = 0
f(0) =0
R.H.L = ` underset (x to 0^(+))(LIM)f(x)`
LET 0 + h = x
`rArr0 + h to x `
`rArrh to 0 `
` underset (h to 0)(lim)(0+h)= underset (h to 0)(lim)(|h|)/(h) `
` underset (h to 0)(lim)(h)/(h) underset (h to 0)(lim)(1)= 1 `
`:'` f(0) `ne` R.H.L.
`:.` f(x) is discontinuous at x = 0


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