InterviewSolution
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{{:((|x|)/(x)","if x ne 0 ),(0"," if x = 0 ):} |
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Answer» Solution :`{{:((|x|)/(x)","if x NE 0 ),(0"," if x = 0 ):}` at x = 0 f(0) =0 R.H.L = ` underset (x to 0^(+))(LIM)f(x)` LET 0 + h = x `rArr0 + h to x ` `rArrh to 0 ` ` underset (h to 0)(lim)(0+h)= underset (h to 0)(lim)(|h|)/(h) ` ` underset (h to 0)(lim)(h)/(h) underset (h to 0)(lim)(1)= 1 ` `:'` f(0) `ne` R.H.L. `:.` f(x) is discontinuous at x = 0 |
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