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(X+Y).(X.Z+Z).(Y'+X.Z)' |
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Answer» (X + Y).(X.Z + Z).(Y' + X.Z)' = (X + Y).((X+1).Z).((Y')' + (X.Z)') (∵ (A + B)' = A' + B' and (A+B).C = A.B + A.C) = (X + Y).(1.Z).(Y + (X'+Z'))(∵ A+1 = 1,(y')' = y and (A.B)' = A' + B') = (X + Y).Z.(Y + (X'+Z'))(∵ 1.Z = Z) = (X + Y).(Y.Z + (X'+Z')) (∵ A.B = B.A) = (X + Y). (Y.(ZX'+Z.Z')) (∵ A.(B+C) = A.B + A.C) = (X + Y).(Y. (ZX' + 0) (∵ Z.Z' = 0) = (X + Y).Y.(ZX') (∵ A+0 = A and A.(B.C) = (A.B).C = A.B.C) = (XY + Y.Y) (ZX') (∵ (A+B).C = A.C + B.C) = (XY + Y).(ZX') (∵ Y.Y =Y) = (X+1).Y. ZX' (∵ (X+1).Y = XY +Y) = (1.Y).ZX' (∵ X+1 = 1) = Y.ZX' (∵ 1.Y = Y) |
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