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x+y+z=15 if 9, x, y, z, a are in A.P. while `(1)/(X)+(1)/(Y)+(1)/(Z)=(5)/(3)if9,X, Y, Z, a` are in H.P., then the value of a will be -A. 1B. 2C. 3D. 9 |
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Answer» Correct Answer - A 9, x, y, z, a are in A.P. x+y+z=15 `rArr3[(9+a)/(2)]=15` ltBrgt a=1 9, X, Y, Z, a are in H.P. `(1)/(9),(1)/(X),(1)/(Y),(1)/(Z),(1)/(a)" are in "A.P.` `(1)/(X)+(1)/(Y)+(1)/(Z)=(5)/(3)rArr3([(1)/(9)+(1)/(a)])/(2)= (5)/(3)rArra=1` |
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