InterviewSolution
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`(x-y-z)^2-(x^2+y^2+z^2)=2(yz-zx-xy)` |
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Answer» `L.H.S. = (x-y-z)^2-(x^2+y^2+z^2)` `=(x^2+y^2+z^2-2xy-2zx+2yz) - (x^2+y^2+z^2)` `=2yz-2zx-2xy` `=2(yz-zx-xy) = R.H.S.` |
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