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xâ3 x+3+6...6~â0) 53 x-3 |
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Answer» (x-3)/(x+3) - (x+3)/(x-3) + 6 6/7 = 0 (x*x - 6x + 9 - x*x - 6x - 9) / (x*x - 9) = - 6 6/7 -12x / (x*x - 9) = -48/7 x/(x*x - 9) = 4/7 7x = 4x*x - 36 4x*x - 7x - 36 = 0 4x*x - 16x + 9x - 36 = 0 4x(x-4) + 9(x-4) = 0 (4x+9)(x-4) = 0 x = -9/4 , 4 If you find this answer helpful then like it. |
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