xample 13 : Hanumappa and his wife Gangamma areusy making jaggery out

1.	xample 13 : Hanumappa and his wife Gangamma areusy making jaggery out of sugarcane juice. They havetocessed the sugarcane juice to make the molasseshich is poured into moulds in the shape of a frustum ofcone having the diameters of its two circular faces asDcm and 35 cm and the vertical height of the mould is4 cm (see Fig. 13.22). If each cm3 of molasses haslass about 1.2g, find the mass of the molasses that ca
Answer» Given, mould is in the shape of a frustum of a cone in which r2= 30/2, r1=35/2 cm, h= 14 cm. Quantity (volume) molasses that can be poured into it= volume of the frustum = π/3 × h (r1² + r2²+r1r2)= 1/3×(22/7) × 14 [(35/2)²+(30/2)²+(35/2 × 30/2]= 44/3[ 306.25 + 225 +262.5]= 44/3 × 793.75= 11641.7 cm³ Given : 1 cm³ of molasses = 1.2 g Mass of the molasses that can be poured into each mould= 11641.7 × 1 2 = 13970.04 g= 13970.04/1000= 13.97 kg [ 1g = 1/1000 kg] Hence, Mass of the molasses that can be poured into each mould= 13.97 kg= 14 kg (approx) Please like the solution 👍 ✔️

xample 13 : Hanumappa and his wife Gangamma areusy making jaggery out of sugarcane juice. They havetocessed the sugarcane juice to make the molasseshich is poured into moulds in the shape of a frustum ofcone having the diameters of its two circular faces asDcm and 35 cm and the vertical height of the mould is4 cm (see Fig. 13.22). If each cm3 of molasses haslass about 1.2g, find the mass of the molasses that ca

Answer»

Given, mould is in the shape of a frustum of a cone in which r2= 30/2, r1=35/2 cm, h= 14 cm.

Quantity (volume) molasses that can be poured into it= volume of the frustum

= π/3 × h (r1² + r2²+r1r2)= 1/3×(22/7) × 14 [(35/2)²+(30/2)²+(35/2 × 30/2]= 44/3[ 306.25 + 225 +262.5]= 44/3 × 793.75= 11641.7 cm³

Given : 1 cm³ of molasses = 1.2 g

Mass of the molasses that can be poured into each mould= 11641.7 × 1 2 = 13970.04 g= 13970.04/1000= 13.97 kg

[ 1g = 1/1000 kg]

Hence, Mass of the molasses that can be poured into each mould= 13.97 kg= 14 kg (approx)

Please like the solution 👍 ✔️