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Xdx + ydy = xdx + ydy/(x2 + y2) |
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Answer» x dx + y dy \(=\frac{x\,dx+y\,dy}{x^2+y^2}\) ⇒ 2x dx + 2y dy \(=\frac{2x\,dx+2y\,dy}{x^2+y^2}\) (Multiply both sides by 2) ⇒ ∫2x dx + ∫2y dy \(=\int\frac{2x\,dx+2y\,dy}{x^2+y^2}\) ⇒ x2 + y2 = ln(x2 + y2) + c (∵ d[ln(x2+y2)] \(=\frac{2x\,dx+2y\,dy}{x^2+y^2})\) |
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