Xe reacts with F_(2) at different ratio to give different types of xenon fluorides. Xe+ Fe rarr XeF_(2) (2:1) Xe +F_(2) rarr XeF_(4) (1:5) Xe + F_(2) rarr XeF_(6) (1: 20) Which of the following option is correct regrading XeF_(2)

Xe reacts with F_(2) at different ratio to give different types of xen

1.	Xe reacts with F_(2) at different ratio to give different types of xenon fluorides. Xe+ Fe rarr XeF_(2) (2:1) Xe +F_(2) rarr XeF_(4) (1:5) Xe + F_(2) rarr XeF_(6) (1: 20) Which of the following option is correct regrading XeF_(2)
Answer» two fluorine OCCUPY equatorial position There are total two BOND pair and two LONE pair present in `XeF_(2)` Its structure is linear and it is isostructural with `I_(3)^(-)` Hybridisation of `XeF_(2)` is `sp^(3)` Answer :C