1.

`XeF_4` disproportionates in water giving reduced and oxidised products What is the ratio of oxidation states of Xe in the reduced and the oxidised products:

Answer» `overset(+4)(6XeF_4)+12H_2Otooverset(0)(4Xe)+overset(+6)(2XeO_3)+24HF+3O_2`


Discussion

No Comment Found

Related InterviewSolutions