1.

Xenon crystabllises in the face- centred cubic lattic and the edge of the unit cell is 620 pm. What is the nearest neighbour distance and what is the radius of xenon atom ?

Answer»

Solution : Herea = 620 PM, d = ?, r = ?
For the face - CENTRED cubic ` = d = a/sqrt2 = 620/1.414 = 438 .5 ` pm ,` r = d/2 = (438.5)/2 = 219. 25 ` pm


Discussion

No Comment Found