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Xenon crystallizes in the face-centred cubic lattice and the edge of the unit cell is `620` pm. What is the nearest neighbour distance and what is the redius of xenon atom?A. 219.20pmB. 438.5 pmC. 265.5 pmD. 536.94 pm

Answer» Correct Answer - A
`(a)(2)/(sqrt(2))`
`=(620)/(2(sqrt(2)))` pm
`r=219.20` pm


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