Xenon crystallizes in the face-centred cubic lattice and the edge of the unit cell is `620` pm. What is the nearest neighbour distance and what is the redius of xenon atom?

Xenon crystallizes in the face-centred cubic lattice and the edge of t

1.	Xenon crystallizes in the face-centred cubic lattice and the edge of the unit cell is `620` pm. What is the nearest neighbour distance and what is the redius of xenon atom?
Answer» Here `a = 620 "pm", d = ?, r = ?` For the face-centred cubic lattice, `d = (a)/(sqrt2) = (620 "pm")/(1.414) = 438.5 "pm"` `r = d//2 = 438.5//2 = 219.25`. Pm

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Xenon crystallizes in the face-centred cubic lattice and the edge of the unit cell is `620` pm. What is the nearest neighbour distance and what is the redius of xenon atom?

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