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Xenon crystallizes in the face-centred cubic lattice and the edge of the unit cell is `620` pm. What is the nearest neighbour distance and what is the redius of xenon atom?A. 438.5 pmB. 219.25 pmC. 420 pmD. 261.5 pm |
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Answer» Correct Answer - A As xenon crystallises in fcc lattice , nearest neighbour distance (d) `=a/sqrt2=(620)/(sqrt2)=620/1414 = 438.5` |
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