xg of tartaric acid is dissolved in 30mL of 0.2M potash solution. The resultant mixture requires20ml of 0.1M HCl for titration. Report the numerical value of x.

xg of tartaric acid is dissolved in 30mL of 0.2M potash solution. The

1.	xg of tartaric acid is dissolved in 30mL of 0.2M potash solution. The resultant mixture requires20ml of 0.1M HCl for titration. Report the numerical value of x.
Answer» Solution :Tartaric ACID is a dibasic acid HOOC-CHOH-CHOH-COOH Gram molecular weight (GMW) = 150G , THEREFORE, GEW = 75g m.eq . Of NaOH =m.eq . Of HCl m.eq. of tartaric acid `=30xx0.2-20xx0.1=6-2=4` Weight of tartaric acid DISSOLVED = Number m.eq`xx(75)/(1000)=(4xx75)/(1000)=0.3` Numerical value of x=0.3