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(xii) 8760057(xiv) 99395055(xv) 100001010x for which the number 71x is divisible by 3. Also.Find all the possible values ofsuch numbers |
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Answer» when a number is divisible by 3 then sum of digits must be divisible by 3.so here 71x = 7+1+x = 8+x = so possible of x are 1, 4, 7. |
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