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`XmL` of `H_(2)` gas effuses through a hole in a container is 5 second. The time taken for the effusion of the same volume of the gas specified below under identical conditions is .A. `10` seconds: `He`B. `20` seconds: `O_(2)`C. `25` seconds: `CO`D. `35` seconds: `CO_(2)` |
Answer» Correct Answer - B `(r_(H_(2)))/(r_(H_(e)))=sqrt((4)/(2))=sqrt(2)` `:.` (a) in incorrect `(r_(H_(2)))/(r_(O_(2)))=sqrt((32)/(2))=4` (b) is correct `(r_(H_(2)))/(r_(C_(O)))=sqrt((28)/(2))=sqrt(14)` (c) is correct `(r_(H_(2)))/(r_(Co_(2)))=sqrt((2)/(44))=sqrt((1)/(12))` (d) is correct. |
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