`xMnO_4^(-) +yH_2O_2 rarr 2Mn^(2+) + 5 H_2O + 9O_2 + Ze^(-)` In this reaction, the values of ` x,y`, and `z`, respectively, are .A. ` 2,5,6`B. ` 5,2, 9`C. ` 3,5,5`D. ` 2,6,6`

`xMnO_4^(-) +yH_2O_2 rarr 2Mn^(2+) + 5 H_2O + 9O_2 + Ze^(-)` In this r

1.	`xMnO_4^(-) +yH_2O_2 rarr 2Mn^(2+) + 5 H_2O + 9O_2 + Ze^(-)` In this reaction, the values of ` x,y`, and `z`, respectively, are .A. ` 2,5,6`B. ` 5,2, 9`C. ` 3,5,5`D. ` 2,6,6`
Answer» Correct Answer - A Redox reaction should be balanced with respect to the number of atoms and ionic charges . To balance Mn atome on both sides, we multiply ` MnO_4^(-)` by `2`. To balance H and O atoms on both sides, we multiply `H_(2)O_(2)` by 5. To balance ionic charge, we add 6 electrons on the right-hand side. `2MnO_(4)^(-)+5H_(2)O_(2) rarr 2Mn^(2+)+5H_(2)O+9O_(2)+6e^(-)`

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`xMnO_4^(-) +yH_2O_2 rarr 2Mn^(2+) + 5 H_2O + 9O_2 + Ze^(-)` In this reaction, the values of ` x,y`, and `z`, respectively, are .A. ` 2,5,6`B. ` 5,2, 9`C. ` 3,5,5`D. ` 2,6,6`

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