1.

XY_(2) dissociates XY_(2)(g) hArr XY(g)+Y(g). When the initial pressure of XY_(2) is 600 mm Hg, the total equilibrium pressure is 800 mm Hg. Calculate K for the reaction Assuming that the volume of the system remains unchanged.

Answer»

50
`100.0`
`166.6`
`400.0`

Solution :`XY_(2)hArrXY+Y`
Initial PRESSURE of `XY_(2)=600mm Hg` ACCORDING to equation
`XY_(2)hArrXY+Y`
`{:("Initial",600,0,0),("At equlibrium",600-P,P,P):}`
TOTAL `=600+P=800P=200`
`K=(200xx200)/(400)=100.0`


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