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`y dx - (x + 2y^(2)) dy = 0` |
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Answer» Correct Answer - ` x = 2y ^(2) +Cy` `y dx = (x + 2y ^(2)) dy rArr (dx)/(dy) = (x )/(y) + 2y ` `therefore (dx)/( dy )- (1)/(y) *x = 2y ` |
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