1.

`y dx - (x + 2y^(2)) dy = 0`

Answer» Correct Answer - ` x = 2y ^(2) +Cy`
`y dx = (x + 2y ^(2)) dy rArr (dx)/(dy) = (x )/(y) + 2y `
`therefore (dx)/( dy )- (1)/(y) *x = 2y `


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