1.

Y g of non-volatile organic substance of molecular mass M is dissolved in 250 g benzene. Molal elevation constant of benzene is K_(b). Elevation in its boiling point is given by:s

Answer»

`M/(K_(B)Y)`
`(4K_(b)Y)/M`
`(K_(b)Y)/(4M)`
`(K_(b)Y)/M`

Solution :`DeltaT_(b)=K_(b)xx(W_(B)xx1000)/(M_(B)xxW_(A))`
`=K_(b)xx((Y_(g))xx(1000 g ))/(Mxx(250G ))`
`(K_(b)xxYxx4)/M=(4K_(b)y)/M`


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