y=tan−1(√1+x2+√1−x2√1+x2−√1−x2),x2<1, then find dydx. – InterviewSolution

1.	y=tan−1(√1+x2+√1−x2√1+x2−√1−x2),x2<1, then find dydx.
Answer» $y = t a n^{- 1} (\frac{\sqrt{1 + x^{2}} + \sqrt{1 - x^{2}}}{\sqrt{1 + x^{2}} - \sqrt{1 - x^{2}}}), x^{2} < 1$ , then find $\frac{d y}{d x}$ .

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