y = ( x - 1) \operatorname{log} ( x - 1) - ( x + 1) \operatorname{log – InterviewSolution

InterviewSolution

1.	y = ( x - 1) \operatorname{log} ( x - 1) - ( x + 1) \operatorname{log} ( x + 1) ,\text{ prove that } \frac { d y } { d x } = \operatorname{log} ( \frac { x - 1} { 1+ x } )
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