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Y1 = a1 sin(wt-2πx/y) and Y2 = a2 sin (wt-2πx/y + €) is |
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Answer» hey there, ● Answer - ∆x = λ(θ+π/2)/2π ● Explanation - Given wave eqns are, y1 = a1sin(ωt-2πx/λ) ...(1) y2 = a2cos(ωt-2πx/λ+θ) y2 = a2sin(ωt-2πx/λ+θ+π/2) ...(2) Comparing (1) & (2), phase difference is ∆θ = θ+π/2 Path difference is given by - ∆x = ∆θ × λ / 2π ∆x = λ(θ+π/2)/2π Hence, path difference is λ(θ+π/2)/2π . Thanks for asking... |
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