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यदि `27^(@)C` ताप तथा 2 bar दाब पर एक गैस का घनत्व `5.46 dm^(-3)` है तो इसका STP पर घनत्व क्या होगा ? |
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Answer» `because m = (dRT)/(P)` `therefore d = (mP)/(RT)` `therefore d prop (P)/(T)" " (because` गैस के लिये m तथा R स्थिर है ) `therefore (d_(1))/(d_(2)) = (P_(1)xx T_(2))/(P_(2) xx T_(1))` `therefore d_(2) = (d_(1)xxP_(2)xxT_(1))/(P_(1)xxT_(2))` `d_(1) = 5.46 g dm^(-3),P_(1) = 2 "bar", T_(1) = 300 K` STP पर, `d_(2) = ?, P_(2) = "bar", T_(2) 273` `therefore d_(2) = (5.46 xx 1 xx 300)/(2xx 273) = 3.0 g dm^(-3)` |
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