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यदि `A=[(0,1),(1,0)]` और `B=[(0-i),(i,0)]` जहां `i^(2)=-1` तो दर्शाइए कि `(A+B)^(2)=A^(2)+B^(2)`. |
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Answer» `A+B=[(0,1),(1,0)+[(0,-i),(i,0)]` `=(0+0,1-i),(1+I,0+0)]=[(0,1-i),1+I,0)]` `:.(A+B)^(2)=[(0,1-i),(1+I,0)]xx[(0,1-i),(1+I,0)]` `=[(1-i^(2),0),(0,1-t^(2))]=[(2,0),(0,2)]`……..1 अब `A^(2)=[(0,1),(1,0)][(0,1),(0,0)]=[(1,0),(0,1)]` तथा `B^(2)=[(0,i),(i,0)][(0,-i),(i,0)]` `=[(-i^(2),0),(0,-i^(2))]=[(1,0),(0,1)]` `:.A^(2)+B^(2)=[(1,0),(0,1)]+[(1,0),(0,1)]` `=[(2,0),(0,2)]`....2 समीकरण 1 व 2 से `(A+B)^(2)=A^(2)+B^(2)` |
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