1.

यदि `A=[(1,2,2),(2,1,2),(2,2,1)]` प्रमाणित कीजिए- `A^(2)-4A-5I=0`

Answer» दिया है- `A=[(1,2,2),(2,1,2),(2,2,1)]`
`A^(2)=A.A=[(1,2,2),(2,1,2),(2,2,1)][(1,2,2),(2,1,2),(2,2,1)]=[(9,8,8),(8,9,8),(8,8,9)]`
`4A=4[(1,2,2),(2,1,2),(2,2,1)]=[(4,8,8),(8,4,8),(8,8,4)]`
तथा `5I=5[(1,0,0),(0,1,0),(0,0,1)]=[(5,0,0),(0,5,0),(0,0,5)]`
अब `A^(2)-4A-5I=[(9,8,8),(8,9,8),(8,8,9)]-[(4,8,8),(8,4,8),(8,8,4)]-[(5,0,0),(0,5,0),(0,0,5)]`
`=[(0,0,0),(0,0,0),(0,0,0)]=0` (शून्य आव्यूह)


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