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    				| 1. | यदि `a=2hati+hatj+hatk, b=hati+2hatj-hatk` व इकाई सदिश c समतलिये है यदि c,a पर लम्ब है तब c=A. `(1)/(sqrt2)(-hatj+hatk)`B. `(1)/(sqrt3)(-hati-hatj-hatk)`C. `(1)/(sqrt5)(hati-2hatj)`D. `(1)/(sqrt3)(hati-hatj-hatk)` | 
| Answer» Correct Answer - A | |