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यदि `A=diag[(1,-2,3)],B=diag.[(3,4,-6)]` और `C=diag[(0,1,2)]` तब `A-2B+3C` ज्ञात कीजिए। |
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Answer» `A=diag[(1,-2,3)]=[(1,0,0),(0,-2,0),(0,0,3)]` `B=diag[(3,4,-6)]=[(3,0,0),(0,4,0),(0,0,-6)]` `C=diag[(3,4,-6)]=[(3,0,0),(0,4,0),(0,0,-6)]` `C=diag[(0,1,2)]=[(0,0,0),(0,1,0),(0,0,2)]` अब `A-2B+34C=A+(-2)B+3C` `=[(1,0,0),(0,-2,0),(0,0,3)]+(-2)[(3,0,0),(0,4,0),(0,0,-6)]` `+3[(0,0,0),(0,1,0),(0,0,2)]` `=[(1,0,0),(0,-2,0),(0,0,3)]+[(-6,0,0),(0,-8,0),(0,0,12)]` `+[(0,0,0),(0,3,0),(0,0,6)]` `=[(1+(-6)+0,0+0+0,0+0+0),(0+0+0,(-2)+(-8)+3,0+0+0),(0+0+0,0+0+0,3+12+6)]` `=[(-5,0,0),(0,-7,0),(0,0,21)]` `diag[(-5,-7,21)]` |
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