1.

यदि `omega` इकाई का घनमूल हो , तो सिद्ध कीजिए कि - `|(1,omega,omega^2),(omega,omega^2,1),(omega^2,1,omega)|`

Answer» `L.H.S=|(1,omega,omega^2),(omega,omega^2,1),(omega^2,1,omega)|`
`=|(1+omega+omega^2,omega,omega^2),(1+omega+omega^2,omega^2,1),(1+omega+omega^2,1,omega)|`
संक्रिया `C_1toC_1+C_2+C_3` से)
`=|(0,omega,omega^2),(0,omega^2,1),(0,1,omega)|(because 1 + omega + omega^2=0)`
`=0=R.H.S`.


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