InterviewSolution
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यदि `omega` इकाई का घनमूल हो , तो सिद्ध कीजिए कि - `|(1,omega,omega^2),(omega,omega^2,1),(omega^2,1,omega)|` |
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Answer» `L.H.S=|(1,omega,omega^2),(omega,omega^2,1),(omega^2,1,omega)|` `=|(1+omega+omega^2,omega,omega^2),(1+omega+omega^2,omega^2,1),(1+omega+omega^2,1,omega)|` संक्रिया `C_1toC_1+C_2+C_3` से) `=|(0,omega,omega^2),(0,omega^2,1),(0,1,omega)|(because 1 + omega + omega^2=0)` `=0=R.H.S`. |
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