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यदि `tan^(-1)""(x-1)/(x-2)+tan^(-1)""(x+1)/(x+2)=(pi)/(4)`, तो x का मान ज्ञात कीजिए। |
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Answer» `tan^(-1)""(x-1)/(x-2)+tan^(-1)""(x+1)/(x+2)=(pi)/(4)` `impliestan^(-1)""((x-1)/(x-2)+(x+1)/(x+2))/(1-(x-1)/(x-2).(x+1)/(x+2))=tan^(-1)1` `implies((x-1)+(x+2)+(x+1)(x-2))/((x-2)(x+2)-(x-1)(x+1))=1` `implies(x^(2)+x-2+x^(2)-x-2)/((x^(2)-4)-(x^(2)-1))=1` `implies(2x^(2)-4)/(-3)=1implies2x^(2)-4=-3` `implies2x^(2)=1impliesx^(2)=(1)/(2)impliesx=+-(1)/(sqrt2)` |
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