1.

Yellow light emitted from a sodium lamp has a wavelength (lamda) of 580nm. Calculate the frequency (v) and the wave number (bar(v)) of the yellow light

Answer»

Solution :`LAMDA = 580 nm = 580 xx 10^(-9) m`
Frequency, `V = (c)/(lamda) = (3.0 xx 10^(8) ms^(-1))/(580 xx 10^(-9) m) = 5.17 xx 10^(14) s^(-1)`
Wave number, `bar(v) = (1)/(lamda) = (1)/(580 xx 10^(-9) m) =1.72 xx 10^(6) m^(-1)`


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