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Answer»

12^2-7^2=(12-7)(12+7)=5*19=95using identity a^2-b^2=(a-b)(a+b)

3x^2+5x+6=0X=-b+-√b^2-4ac/2aX=-5+-√25-4*6*3/6X=-5+-√25-52/6X=-5+-√-27/6hence this equation has imaginary roots



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