You are given the following bond energy data E_(H-H) = 104.2 kcal mol ^(-1),E_(F-F) = 36.6kcal mol ^(-1), E_(H-F) = 134.6 kcal mol ^(-1) On the basis of this data, eletronegativity of flurine will be ……….

You are given the following bond energy data E_(H-H) = 104.2 kcal mol

1.	You are given the following bond energy data E_(H-H) = 104.2 kcal mol ^(-1),E_(F-F) = 36.6kcal mol ^(-1), E_(H-F) = 134.6 kcal mol ^(-1) On the basis of this data, eletronegativity of flurine will be ……….
Answer» Solution :Suppose the electronegativity of H and F are reprsented as `chi_(H) and chi_(F)`RESPECTIVELY . APPLING Pauling's formula `\|chi_(H)- chi_(F) \|=0.208sqrt(Delta) ` `Delta= BE (H-F) - sqrt(BE(H-H)xxBE(F-F))` `= 134.6 - sqrt(104.2xx36.6)` `= 134.6 - 61.8`kcal mol `^(-1)` 72. 8kcal mol `^(-1)` `therefore\|chi_(H)- chi_(F) \|=0.208sqrt(72.8) = 1.77` As `chi_(F)gt chi_(H),chi_(F)= 1.77 + chi_(H) = 1.77+2.1 = 3.87`