1.

You are given the following group of particles ,n_(1) represents the number of molecules with speed v_(1) Calculate (i)average speed (ii)rms speed (iii)Most probable speed.

Answer»

Solution :(i)AVERAGE speed
`v_(ANG)=(n_(1)v_(1)+n_(2)v_(2)+n_(3)v_(3)+n_(4)v_(4)+n_(5)v_(5))/((n_(1)+n_(2)+n_(3)+n_(4)+n_(5))`
`=(73)/(23)=3.17 MS^(-1)`
(ii)root mean square speed is
`V_(RMS)=((n_(1)v_(1)^(2)+n_(2)v_(2)^(2)+n_(3)v_(3)^(2)+n_(4)v_(4)^(2)+n_(5)v_(5)^(2))/(n_(1)+n_(2)+n_(3)+n_(4)+n_(5)))^(1//2)`
`=((2xx1+4xx4+8xx9+6xx16+3xx25)/(2+4+8+6+3))^(1//2)=3.36 ms^(-1)`
(iii)Most probable speed 3m/s by which largest molecules are moving at any time.


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