You are given the followingspecies :PH_(3), P_(2)H_(6)^(2+), P_(2) H_(5)^(+) and PH_(4)^(+)Which of these has least covalent P-H character and why ?

You are given the followingspecies :PH_(3), P_(2)H_(6)^(2+), P_(2) H_(

1.	You are given the followingspecies :PH_(3), P_(2)H_(6)^(2+), P_(2) H_(5)^(+) and PH_(4)^(+)Which of these has least covalent P-H character and why ?
Answer» Solution :GREATER the FORMAL charge distribution on each P-H BOND, less is the covalent character. Formal charge distribution=`(" Total charge")/("Number of P-H bonds")` THUS , the values for formal charge distribution will be ` PH_(3) = (0)/(3) = 0 ,P_(2) H_(6)^(2+) = (2)/(6) = 0.33, P_(2)H_(5)^(+) = (1)/(5) = 0.2, PH_(4)^(+) = (1)/(4) = 0 . 25` As ` P_(2) H_(6)^(2+)`has highest formal charge distribution, it will have least covalent character.