You have a mixture of three liquids A, B and C. There is a targe difference in the boiling points of A and rest of the two liquids i.e., B and C. Boiling point of liquids B and C are quite close. Liquid A boils at a higher temperature than B and C and boiling point B is lower than C. How will you separate the comonents of the mixture. Draw a diagram showing set up of the apparatus for the process

You have a mixture of three liquids A, B and C. There is a targe diffe

1.	You have a mixture of three liquids A, B and C. There is a targe difference in the boiling points of A and rest of the two liquids i.e., B and C. Boiling point of liquids B and C are quite close. Liquid A boils at a higher temperature than B and C and boiling point B is lower than C. How will you separate the comonents of the mixture. Draw a diagram showing set up of the apparatus for the process
Answer» Solution :Order of boiling point `A gt gt gt B gt C` The boiling point of LIQUID A is much higher than those of liquid B and C whose b.p are quite does therefore separate liquid A by simple distillation using the apparatus shown in figure as under. The b.p. of liquid B and C are quite close but are much lower than that of liquid A, therefore, MIXTURE of liquid B and C will DISTIL together leaving BEHIND liquid A. On further heating liquid A will distil. Mixture B and C has less difference in their boiling point. So following arrangement is done for SEPARATION of B and C Now, place the mixture of liquid B and C in a flask fitted with a fractionating column as shown in figures. Since the b.p of liquid B is lower than that of liquid C, therefore, on fractional distillation first liquid B will distil over and the liquid C.