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You measure two quantities as `A=1.0m+-0.2m`,`B=2.0m+-0.2m`. We should report correct value for `sqrt(AB)` asA. `1.4m+-0.4m`B. `1.41m+-0.15m`C. `1.4m +-0.3 m`D. `1.4 m+-0.2m` |
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Answer» Correct Answer - D `"Given"," "A=1.0m+-0.2m, B=2.0m+-0.2m` `"Let"," "Y=sqrt(AB)=sqrt((1.0)(2.0))=1.414 m ` Rounding off to two significant digit Y=1.4m `(DeltaY)/Y=1/2[(DeltaA)/A+(DeltaB)/B]=1/2[(0.2)/(1.0)+(0.2)/(2.0)]=(0.6)/(2xx2.0)` `Rightarrow " "DeltaY=(0.6Y)/(2xx2.0)=(0.6xx1.4)/(2xx2.0)=0.212` Rounding off to one significant digit `DeltaY==0.2m` Thus, correct value for `sqrt(AB)=r+Deltar=1.4+-0.2m` |
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