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The no. of terms in the answer is 49.

  • First you should agree that;

no. of 4's = no. of the fractional parts

  • The first fraction \(\frac{1}{2}\) can be written as( \(\frac{1}{1}-\frac{1}{2}\)) .
  • The denominator of \(\frac{1}{1}\) ,i.e.,1 indicates that it is 1st fraction.
  • Similarly, in the second fraction \(\frac{1}{6}\) can be written as (\(\frac{1}{2}-\frac{1}{3}\) ). 
  • Here also, the denominator of \(\frac{1}{2}\) ,i.e., 2 indicates that it is 2nd term.
  • Hence in( \(\frac{1}{49}-\frac{1}{50}\)) , the denominator of \(\frac{1}{49}\) ,i.e. , 49 indicates that it is 49th term
  • And hence the total no. of fraction = 49 = no. of 4's.
  • So total 49 times 4 are 49×4


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