1.

Z_(2)undergo disproportion in an alkaline medium into a mixture of Z^(-) and ZO_(3)^(-). Equivalent mass of Z_(2)in the reaction is: [given that atomic mass of Z is 80 gm/mol]

Answer»

96
48
64
32

Solution :It is a disproportionation redox reaction
`3Z_(2) rarr 5Z^(-) + ZO_(3)^(-)` ……..N FACTOR of `Z_(2)= 5//3`
`therefore` Equivalent mass of `Z_(2)= (M^(@))/(5//3) = (3)/(5) [160] = 96`


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