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zeroes ait15.In Fig. 4, AB 11 DE and BD 11 EF. Prove that DC-CFX AC. |
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Answer» InΔABC, we have CD/DA = CE/EB as AB || DEinΔCDB, we have CF/FD = CE/EB as EF || BD hence we get CD/DA = CF/FD=>Reciprocals: DA/CD = FD /CF=> Add 1 on bothsides: AC /CD = DC/CF => DC^2 = CF * AC |
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