1.

zeroes ait15.In Fig. 4, AB 11 DE and BD 11 EF. Prove that DC-CFX AC.

Answer»

InΔABC, we have CD/DA = CE/EB as AB || DEinΔCDB, we have CF/FD = CE/EB as EF || BD

hence we get CD/DA = CF/FD=>Reciprocals: DA/CD = FD /CF=> Add 1 on bothsides: AC /CD = DC/CF

=> DC^2 = CF * AC



Discussion

No Comment Found